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The limiting reactant

The same piece of magnesium in a little and a lot of acid.

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What you do

1. Add one piece of magnesium to each tube.
2. Tube 1: the fizzing stops but magnesium is left. Which reactant ran out? (5 mL × 0.5 M = 0.0025 mol H⁺ < 2 × 0.002 mol)
3. Tube 2: the magnesium disappears completely. Here the acid is in excess. Compare the hydrogen volumes: 30 mL and 48 mL.
4. How many moles of hydrogen formed in tube 1 (mol)?

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